Given the following data:
Reaction Energy Change (in $kJ$)
$Li_{(s)} \to Li_{(g)}$ $161$
$Li_{(g)} \to Li^{+}_{(g)}$ $520$
$\frac{1}{2} F_{2(g)} \to F_{(g)}$ $77$
$F_{(g)} + e^- \to F^{-}_{(g)}$ (Electron gain enthalpy)
$Li^{+}_{(g)} + F^{-}_{(g)} \to LiF_{(s)}$ $-1047$
$Li_{(s)} + \frac{1}{2} F_{2(g)} \to LiF_{(s)}$ $-617$

Based on the data provided,the value of electron gain enthalpy of fluorine would be $kJ\ mol^{-1}$.

  • A
    $-300$
  • B
    $-350$
  • C
    $-328$
  • D
    $-228$

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The energy absorbed by each molecule $(A_2)$ of a substance is $4.4 \times 10^{-19} \ J$ and bond energy per molecule is $4.0 \times 10^{-19} \ J.$ The kinetic energy of the molecule per atom will be $...... \times 10^{-20} \ J$

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